Handling sea water with a water trap seems to give a better yield of m-state (better in terms of quantity
and density of m-state in relation to Mg(OH)2) for the wet method to follow (test with two identical jars
with selected and unselected seawater). Working with the water trap on site gives the advantage of carrying
much less water.
My equipment is :
Water Trap (three stage T-trap)
Boat pump 12V 500lt/h
Old car Battery
Battery Charger(at home)
Of course it is very simple to go and fill a container with seawater instead of carrying pumps, watertraps, car
batteries etc and also have people looking and wondering what you're doing with this peculiar equipment. So I
practiced the method on two samples of water just to have an idea if it's worth getting to all that trouble.
But my experiment was not precise. I did not count the drops of lye nor the difference of the precipitates. I only
counted the pH. However I brought them at the same pH and the precipitate was more at the watertrap sample.
So I decided to have a second (precise) experiment.
Before going on with the experiment itself, I would like to mention an experience from the field of
electronics:
For about two years of my professional life I performed measurements on TV transponders. One of those was the
measurement of the electronic noise level.
How did we do it?
We did it indirectly because every unit (our instruments too) add noise. So how could we separate transponder noise
from the other noise (how can we separate m-state from regular precipitate)?
This is what we do:
We take a "white noise generator", we put it at the transponder input and start to induce more and more noise (from
the generator). At the same time we watch at the screen of the spectrum analyzer the noise level (the "grass") to
get higher and higher. When it gets double (3db difference) we stop.
What has happened now? The noise was doubled. This means that the generator produced the same noise as the
transponder did. So if I read the noise level from the generator panel, this is the measurement that I was looking
for. Because it's the same that the transponder produces.
What does it have to do with Ormus?
Suppose we want to measure the Ormus in the sea precipitate. If we find a way to double it and measure the
difference then this is the amount that we were looking for.
If we set a watertrap at a ratio 1/2 will the Ormus have doubled?
If this is true then we measure the difference between "normal" precipitate and "x2" precipitate. This difference
will be the answer to the question: "How much of the precipitate is m-state?"
First we have to find out if we are in the "linear part of the curve". For this reason I performed the same
experiment with the measurements of precipitate for three different types of water:
"Normal", "x12" and "x80"
In this way I found that (roughly) "yes we are in the linear part of the curve".
Since the "x80" setting gave 52% more precipitate, then our quantity is the 1/80 of it.
The question now is:
"If the quantity of the precipitate shows no difference does this mean that there is no difference in the
quality also?" As an example lets suppose that we have MgCl with simple Mg or m-Mg. After the watertrap we may have
more MgCl with m-Mg but the concentration of the total MgCl may have not changed at all. I believe that this
mechanism also works (maybe it's better not to get rid of MgOH after the Wet Method).
Now the experiment:
At the seashore:
I fill a bottle (1Lt) with seawater just for the experiment. I have also brought 2 containers (12Lt each) to
collect water trough the watertrap for the Wet Method. As soon as I start pumping I discover that I have a problem
with the watertrap. So I have to reduce the ratio to 1/12. I fill the containers.
At home:
I fill two jars. The first with "NORMAL" water and the second with "x12"
The height of water is 16.6cm at both of them.
Before I start with the lye I measure the pH and I have the first surprise:
"NORMAL" 8.5
"x12" 8.4
I repeat the measurement again and again. I bring the second pH meter (after the "accident" which made me throw the
dead sea precipitate I bought a second meter just to verify that the first meter was correct and the fault was
totally mine).
The measurement is correct.
THE WATERTRAP SEAWATER HAS A pH 0.1 LOWER THAN NORMAL SEAWATER.
Something is different after all.
I start adding the lye solution.
Every 10 drops I measure the pH and write it down.
In the morning (after more than 6 hours) I measure the height of the precipitate:
"NORMAL"
4.4cm
"x12" 4.7cm (= 4.4 + 6.8%)
CONCLUSION:
x12 WATERTRAP SEAWATER GAVE 6.8% MORE
PRECIPITATE THAN NORMAL SEAWATER.
We must note that we have much more of total m-state difference because of two reasons. The first reason is the one
I mentioned earlier with the example of MgCl. Something we can suspect but cannot prove without an assay.
The second reason however is more certain because it comes through simple logic: THE 6.8% DIFFERENCE IS 100%
m-state (it came because it reacted to magnets) Of course there is a correction here that we have to make.
Instead of "100% m-state" we should write: "100% molecules containing at least 1 m-state atom each".
Since m-state is a small portion of the precipitate from normal seawater, 6.8% makes a great difference:
If we suppose that we have 5% m-state in the precipitate of normal seawater then an increase of 6.8% gives
more than the double.
In my previous effort even though I didn't measure it I have the impression that the difference was even greater
(the selection ratio of the watertrap was close to 1/100).
Another obvious possibility is that we may find a lot more than 11 kinds of m-state since even undetectable traces
will be multiplied by the watertrap.
The experiment was very simple. Since there are ORMUS products from seawater it is logical to assume that others
have made the experiment before I did. However I can't find any relative information. I would appreciate any
comments, opinions and of course information. I believe that the experiment must be verified by others too.
Nikos (Runikos)
Runikos@in.gr
Free eBook on
Ormus
Complete the
form below to receive a
FREE eBook on Ormus
*
*
*
Regardless of how our products may be used in other countries, or anything
that you may have heard or read about Ormus Minerals or Ormus products, under
FDA law in the United States it is illegal for a manufacturer to make any
medical claims for health supplements. None of the products offered for sale on
our website or direct to retail consumers are intended to be used in the
treatment or mitigation of any disease state.
All statements made by Ormus Minerals or on the Ormus website are intended for informational purposes only.
The statements made here have not been evaluated by the FDA, and our products are not intended
to diagnose, treat, cure or prevent any disease. Health decisions are much too
important to be made without the advice of a health care practitioner.
As with any dietary or herbal supplement, you should advise your health care
practitioner of the use of this product. If you are nursing, pregnant, or
considering pregnancy, you should consult your health care practitioner prior to
using any health supplement product.